Finding the Coefficient of Kinetic Friction

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SUMMARY

The discussion focuses on calculating the Coefficient of Kinetic Friction for a 252kg trunk being slid across carpeting with a horizontal force of 625 Newtons. The coefficient is determined using the equation Ffriction = µFnormal, where Fnormal is equal to the gravitational force acting on the trunk. When an additional 56kg trunk is placed on top, the total weight increases, affecting the normal force and thus the coefficient of kinetic friction. The horizontal force required to maintain constant velocity for both trunks can also be calculated using the same principles.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of force, mass, and acceleration
  • Knowledge of friction and its coefficients
  • Ability to apply basic algebra to solve equations
NEXT STEPS
  • Learn how to calculate the Coefficient of Kinetic Friction using different materials
  • Study the effects of additional mass on frictional forces
  • Explore the relationship between force, mass, and acceleration in various scenarios
  • Investigate real-world applications of kinetic friction in moving objects
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as professionals in fields requiring an understanding of frictional forces in practical applications.

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Homework Statement



A worker at a moving company places a 252kg trunk on a piece of carpeting and slides it across the floor at a constant velocity by exerting a horizontal force of 625 Newtons on the trunk.

a) What is the Coefficient of Kinetic Friction?

b) What happens to the coefficient of kinetic friction if another 56kg trunk is placed on top of the 252kg trunk?

c) What horizontal force must the mover apply to move the combination of the two trunks at a constant velocity?

Homework Equations


F=MA
Ffriction=µFnormal

The Attempt at a Solution



I have absolutely no idea how to find the coefficient of kinetic friction because I am only able to get force normal by using Fg=mg because its not moving up or down so Fn and Fg are equal. That's about it. Thankz
 
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If the velocity is constant, it means that a=0, right?
So what would that mean if we apply that on ΣF=ma?
 

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