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Finding the components of an electric field.

  1. Sep 6, 2012 #1
    1. The problem statement, all variables and given/known data
    What is the electric field at a point when the force on a 1.05μC charge placed at that point is (3.0i-3.9j)x10^-3 N? (E=αi+βj N/C).
    a) Find α
    b) Find β

    3. The attempt at a solution
    first i took the force and solved for the vector sum of the components:
    √[(3x10^-3)^2 + (3.9x10^-3)^2]→ 4.92x10-3 so F=4.92x10^-3

    to find the electric field the equation is E=F/q:
    E=(4.92x10^-3)/(1.05x10^-6)=4685, assuming that is all correct, how do i get the components of an electric field? basically with 4685 how do i get the components?
     
  2. jcsd
  3. Sep 6, 2012 #2
    Isn't the electric field intensity vector equal to the vector force divided by the charge?
     
  4. Sep 7, 2012 #3
    yes...E=F/q, which i used
     
  5. Sep 8, 2012 #4
    Yes, but this equation also applies component-by-component. F is a vector and q is a scalar. F divided by q, component-by-component, gives the new vector E. This is how you get the individual components.
     
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