- #1

bfusco

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## Homework Statement

What is the electric field at a point when the force on a 1.05μC charge placed at that point is (3.0i-3.9j)x10^-3 N? (E=αi+βj N/C).

a) Find α

b) Find β

## The Attempt at a Solution

first i took the force and solved for the vector sum of the components:

√[(3x10^-3)^2 + (3.9x10^-3)^2]→ 4.92x10-3 so F=4.92x10^-3

to find the electric field the equation is E=F/q:

E=(4.92x10^-3)/(1.05x10^-6)=4685, assuming that is all correct, how do i get the components of an electric field? basically with 4685 how do i get the components?