Finding the Composition of Relations

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Homework Help Overview

The discussion revolves around finding the composition of two relations, R and S, specifically the relation R^-1 o S^-1. Participants are exploring the definitions and properties of relations and their inverses.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to identify the inverses of the given relations R and S. There is uncertainty about how to apply the definition of composition without additional sets typically provided in exercises. Questions arise regarding the necessity and role of these additional sets.

Discussion Status

Some participants have provided insights into the composition process, noting specific pairs that result from the mappings of the inverses. There is ongoing exploration of the definitions and the relationships between the sets involved, with no explicit consensus reached.

Contextual Notes

Participants mention the usual presence of additional sets A, B, and C in their exercises, which are typically related to the domains and ranges of the relations. The discussion includes the identification of the domains of R and S, but lacks clarity on how these relate to the current problem.

1MileCrash
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Homework Statement



R = { (1,2), (3,5), (2,2), (2,5) }
S = { (2,1), (5,3), (5,1), (5,5) }

Explicitly find the relation R^-1 o S^-1

Homework Equations





The Attempt at a Solution



This was on my test.

First I just wrote down the inverses:

R^-1 = { (2,1), (5,3), (2,2), (5,2) }
S^-1 = { (1,2), (3,5), (1,5), (5,5) }

I didn't know what to do because the definition we learned defines 3 other sets, and all of the exercises in my test book has those 3 other sets defined.

For example, there are usually sets A, B, and C along with the sets R and S. So I have no idea how I can apply the definition to do this.
 
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1MileCrash said:

Homework Statement



R = { (1,2), (3,5), (2,2), (2,5) }
S = { (2,1), (5,3), (5,1), (5,5) }

Explicitly find the relation R^-1 o S^-1

Homework Equations


The Attempt at a Solution



This was on my test.

First I just wrote down the inverses:

R^-1 = { (2,1), (5,3), (2,2), (5,2) }
S^-1 = { (1,2), (3,5), (1,5), (5,5) }
So S^{-1} "maps" 1 to 2 and R^{-1} maps 2 to 1. Therefore R^{-1}oS^{-1} maps 1 to 1 and contains the pair (1, 1).

R^{-1} also maps 2 to 2 so R^{-1}oS^{-1} also maps 1 to 2 and contains the pair (1, 2).

I didn't know what to do because the definition we learned defines 3 other sets, and all of the exercises in my test book has those 3 other sets defined.
What 3 sets?

For example, there are usually sets A, B, and C along with the sets R and S. So I have no idea how I can apply the definition to do this.
fog contains the pair (a, b) if and only if there exist some c such that g contains (a, c) and f contains (c, b).
 
Last edited by a moderator:
So (3,3) is in the composition because we have (5,3) and (3,5)?
 
1MileCrash said:
So (3,3) is in the composition because we have (5,3) and (3,5)?
(3, 3) is in \displaystyle R^{-1}\circ S^{-1} because, (3, 5) is in S^{-1} and (5, 3) is in R^{-1}\ .
 
I think the other three sets in my definition are A, B, and C and are dupposed to be the domain of R, the Range of R/domain of S, and the range of S.

Sound reasonable?
 
1MileCrash said:
I think the other three sets in my definition are A, B, and C and are supposed to be the domain of R, the Range of R/domain of S, and the range of S.

Sound reasonable?
As Halls said earlier, "What 3 sets?"

The domain of R is {1,2,3}.

The domain of S is {2,5}.

etc.
 

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