Finding the current and the voltage across each resistor

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Homework Help Overview

The problem involves finding the current and voltage across multiple resistors in a circuit with a specified voltage source. The resistors have given values, and the configuration of the circuit is under discussion.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the configuration of resistors, particularly whether certain resistors are in series or parallel. There is an attempt to simplify the circuit by combining resistors and questioning the relationships between them.

Discussion Status

The discussion is active, with participants clarifying the arrangement of resistors and correcting misunderstandings about their configuration. Some guidance has been provided regarding the series and parallel relationships in the circuit.

Contextual Notes

There is a mention of a study guide context rather than a formal homework assignment, which may influence the approach to the problem. The original poster expresses uncertainty about the provided current values and the method to derive them.

Lopez
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Homework Statement


Find the current and the voltage across each resistor.

volts is 24v
R1=270 ohms
R2=330 ohms
R2=1.2k ohms
R4=1.2k ohms


Homework Equations





The Attempt at a Solution


This is not a homework its more like a study guide.
He gave us the answer for just the currents which are
IR1=20
IR2=20
IR3=10
IR4=10
But not sure how he got that.
this is what i did but don't know how to go from there:
(270+330)|| (1.2k||1.2k)
600||600
R=300
 

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Hi Lopez. Welcome to physics forums!

The 270 and 330 are in series with the 600, not parallel.

Chet
 
Lopez said:
(270+330)|| (1.2k||1.2k)
Having reduced the (1.2k||1.2k) to an effective 0.6k, what is the relationship of that in the circuit to R1 and R2?
 
ahh yes there was the problem,after 1.2 k and the other 1.2k were combined it becomes one resistor in series with the (r1 and R2). Thanks!
 

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