Finding the Derivative of 2sin(x) - 5e^x

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SUMMARY

The derivative of the function 2sin(x) - 5e^x is definitively calculated as -2cos(x) - 5e^x. This conclusion is reached through standard differentiation rules, confirming that the integration constant is not necessary in this context. The discussion emphasizes the importance of confidence in solving calculus problems and seeking reassurance when needed.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically differentiation.
  • Familiarity with trigonometric functions and their derivatives.
  • Knowledge of exponential functions and their derivatives.
  • Ability to apply the chain rule and product rule in calculus.
NEXT STEPS
  • Review the rules of differentiation for trigonometric functions.
  • Study the differentiation of exponential functions, particularly e^x.
  • Practice solving derivatives of composite functions using the chain rule.
  • Explore the concept of integration constants in calculus problems.
USEFUL FOR

Students studying calculus, particularly those focusing on differentiation, as well as educators seeking to reinforce concepts related to trigonometric and exponential functions.

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Homework Statement


(2sinx - 5e^x)


The Attempt at a Solution


is it just...
-2cosx - 5e^x
 
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Well, yes. Plus an integration constant. Why would you think otherwise?
 
I don't know...I always second guess myself so I love reassurance...thank you!
 

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