Finding the Derivative of 2sin(x) - 5e^x

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BuBbLeS01
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Homework Statement


(2sinx - 5e^x)


The Attempt at a Solution


is it just...
-2cosx - 5e^x
 
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Well, yes. Plus an integration constant. Why would you think otherwise?
 
I don't know...I always second guess myself so I love reassurance...thank you!