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Glissando
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Homework Statement
Find the maximum and minimum values of the function f(x) = 2sin2x-2sinx on the interval [-pi, pi]]
Homework Equations
first derivative
The Attempt at a Solution
f'(x) = 4sinxcosx-2cosx
0 = 2cosx (2sinx-1)
0 = 2sinx-1, sinx = 1/2, x = pi/6, 5pi/6
0 = 2cosx, cosx = 0, x = pi/2
I got that MIN = -0.5 (plugged pi/6 and 5pi/6 into the original function) but I can't seem to find where MAX @4 is.
Thank you!
Thank you!
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