Finding the derivative of a function with a radical

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The discussion focuses on finding the derivative of a function involving a radical. The user initially transformed the radical into an exponent and applied the product and chain rules but became confused during simplification. Clarifications were provided regarding the difference between finding a differential and a derivative. The user ultimately shared their work, indicating they were stuck at a specific point in the calculation. The conversation emphasizes the importance of showing steps in solving derivatives for better assistance.
waffletree
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Homework Statement


e1bbd57bb281ee733177266492e355.gif

Find the differential

Homework Equations


Chain rule : dy/du=dy/du*du/dx
Product rule: f(x)g'(x) + g(x)f'(x)

The Attempt at a Solution


I have tried to move the radical to the top of the equation by making it into an exponent (x^2+1)^-1/2. I then used the product rule and the chain ruleIand i got lost somewhere simplifying it beyond that.
 
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Hello Waffle, :welcome:

PF culture pushes me to ask this :smile:

Where were you when you got stuck ? In other words: show us how far you got and why you think you were lost at that point ...
 
waffletree said:

Homework Statement


e1bbd57bb281ee733177266492e355.gif

Find the differential

Homework Equations


Chain rule : dy/du=dy/du*du/dx
Product rule: f(x)g'(x) + g(x)f'(x)

The Attempt at a Solution


I have tried to move the radical to the top of the equation by making it into an exponent (x^2+1)^-1/2. I then used the product rule and the chain ruleIand i got lost somewhere simplifying it beyond that.

Show us what you got. Maybe your final,answer is correct, and maybe it isn't; we cannot tell if you will not show it to us.
 
waffletree said:

Homework Statement


e1bbd57bb281ee733177266492e355.gif

Find the differential

Homework Equations


Chain rule : dy/du=dy/du*du/dx
Product rule: f(x)g'(x) + g(x)f'(x)

The Attempt at a Solution


I have tried to move the radical to the top of the equation by making it into an exponent (x^2+1)^-1/2. I then used the product rule and the chain ruleIand i got lost somewhere simplifying it beyond that.
Please show us what you did. Your steps of using the product rule followed by the chain rule are the right approach.
Also, do you need to find the differential or the derivative? They are related, but not the same.
 
Mark44 said:
Please show us what you did. Your steps of using the product rule followed by the chain rule are the right approach.
Also, do you need to find the differential or the derivative? They are related, but not the same.
Sorry I meant to put derivative,
This is where I got stuck at
6x(x^2+1)^-1/2
6x*d/dx(x^2+1)^-1/2+(x^2+1)^-1/2*6
6x*1/2(x^2+1)^-3/2+(x^2+1)^-1/2*6
 
BvU said:
Hello Waffle, :welcome:

PF culture pushes me to ask this :smile:

Where were you when you got stuck ? In other words: show us how far you got and why you think you were lost at that point ...

Sorry I meant to put derivative,
This is where I got stuck at
6x(x^2+1)^-1/2
6x*d/dx(x^2+1)^-1/2+(x^2+1)^-1/2*6
6x*1/2(x^2+1)^-3/2+(x^2+1)^-1/2*6
 
waffletree said:
Sorry I meant to put derivative,
This is where I got stuck at
6x(x^2+1)^-1/2
6x*d/dx(x^2+1)^-1/2+(x^2+1)^-1/2*6
6x*1/2(x^2+1)^-3/2+(x^2+1)^-1/2*6

##\frac{d}{dx} [(x^2+1)^{-1/2}] = (-1/2) (x^2+1)^{-3/2} \cdot \frac{d}{dx} (x^2+1) = -x(x^2+1)^{-3/2}##.
 
Ray Vickson said:
##\frac{d}{dx} [(x^2+1)^{-1/2}] = (-1/2) (x^2+1)^{-3/2} \cdot \frac{d}{dx} (x^2+1) = -x(x^2+1)^{-3/2}##.
Thank you
 

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