Finding the derivative of an unknowable inverse function

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Homework Help Overview

The problem involves finding the derivative of an inverse function, specifically g'(5), where g(x) is the inverse of the function f(x) = x^5 + 2x^2 + 2x. The original poster expresses difficulty in determining the inverse function and subsequently finding the necessary derivative.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the derivative rule for inverses but struggles with finding the value of x such that f(x) = 5. Some participants suggest evaluating simple values of x to identify where f(x) equals 5.

Discussion Status

The discussion has seen participants exploring potential values for x and confirming that x=1 satisfies the equation f(x)=5. However, there is no explicit consensus on the method or reasoning beyond this point.

Contextual Notes

The original poster notes the challenge of finding x in the equation f(x) = 5, which is critical for applying the inverse derivative rule. There is an indication of imposed homework constraints regarding the use of specific methods or approaches.

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Homework Statement



The function f(x) has an inverse function, g(x). Find g'(5).

Homework Equations



[itex]f(x) = x^5 + 2x^2 + 2x[/itex]

The Attempt at a Solution



I don't see how I can possibly find the inverse of this function. So I opted to use the derivative rule for inverses.

[itex]f'(x) = 5x^4 + 4x + 2[/itex][itex]5 = x^5 + 2x^2 + 2x[/itex]This doesn't help me either. I need to solve for x in the second equation and substitute that x in the derivative. In essence, I can't find x of f(x), and without that I can't find the value of f'(x), which is the reciprocal of g'(x).

Any help would be appreciated!
 
Last edited:
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Try a few simple values of x, you will quickly find an x where f(x)=5.
 
LCKurtz said:
Try a few simple values of x, you will quickly find an x where f(x)=5.

Oh wow. x=1. That was very foolish of me! Thank you for your time man.
 
The answer is g'(5)=1/11 . If anyone is curious.
 

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