Finding the Direction Vector of a Line: Tips and Tricks

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To find the direction vector of a line given in the form ax + by + c = 0, the slope can be derived from the equation, where a and b represent the coefficients. The direction vector can be expressed as (1, m), with m being the slope calculated from the rearranged equation. The discussion also highlights the importance of clarifying the equation type, as initial confusion arose with a plane equation. Participants engage in light banter about the age of the thread and the relevance of responses. Understanding the slope is key to determining the direction vector effectively.
Nevermore
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How would I find the direction vector of a line given in the form ax + by + cz +d =0?

Thankyou.
 
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I see an equation of a plane, not a line.
 
Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...
 
Nevermore said:
Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...
For a line, (1,m) is always a directional vector where m is the slope. Can you find the slope?
 
Yeah - I thought it would be something simple like that. Thanks for your help.
 
You're welcome :smile:
 
Thanks for asking that Q, it helped me too
 
I don't think there's a need to thank someone who started a thread two years ago and have not posted since.
 
LORL... Thanks for pointing that out. ( At least you still logon)
 

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