Translation and rotation of quadric surface

In summary, the translation and rotation of quadric surfaces involve manipulating their equations to change their position and orientation in three-dimensional space. Translation involves shifting the surface along the x, y, or z axes, while rotation requires transforming the coordinates based on specific angles around these axes. The resulting equations describe the new positions and orientations of the surfaces, which can include ellipsoids, hyperboloids, and paraboloids, allowing for a comprehensive understanding of their geometric properties and transformations.
  • #1
songoku
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Homework Statement
This is not homework. I try to study calculus by myself using James Stewart book and below is part of text that I want to ask about
Relevant Equations
Not sure
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I want to ask how ##Ax^2+By^2+Cz^2+Dxy+Eyz+Fxz+Gx+Hy+Iz+J=0## can be brought to ##Ax^2+By^2+Cz^2+J=0## or ##Ax^2+By^2+Iz=0## using translation and rotation. There is no explanation in the book. What kind of translation and rotation are needed?

Thanks
 
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  • #2
(1) The constants in the various forms are not the same.

(2) The variables int he various forms are not the same.

The general form can be written [tex]
\begin{pmatrix} x & y & z \end{pmatrix} \begin{pmatrix} A & \frac12D & \frac12 F \\ \frac12 D & B & \frac12 E \\ \frac12 F & \frac12 E & C \end{pmatrix} \begin{pmatrix} x \\y \\ z \end{pmatrix} + \begin{pmatrix} G & H & I \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} + J = \mathbf{x}^TM\mathbf{x} + \mathbf{b}^T \mathbf{x} + J = 0.[/tex] Now [itex]M[/itex] is symmetric, so its eigenvalues are real and it has a basis of orthogonal eigenvectors; thus there exists a rotation (ie. a matrix [itex]R[/itex] with determinant 1 such that [itex]R^{-1} = R^T[/itex]) such that [itex]R^{-1}MR[/itex] is diagonal. What happens if you now set [itex]\mathbf{x} = R\mathbf{X}[/itex] in the general form and complete the squares in each variable for which the corresponding diagonal entry of [itex]R^{-1}MR[/itex] is non-zero?
 
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  • #3
songoku said:
I try to study calculus by myself using James Stewart book...

I want to ask how ##Ax^2+By^2+Cz^2+Dxy+Eyz+Fxz+Gx+Hy+Iz+J=0## can be brought to ##Ax^2+By^2+Cz^2+J=0## or ##Ax^2+By^2+Iz=0## using translation and rotation. There is no explanation in the book.

They took out that whole chapter? Nice! I remember *hating* that chapter. :oldruck:
 
  • #4
pasmith said:
(1) The constants in the various forms are not the same.

(2) The variables int he various forms are not the same.

The general form can be written [tex]
\begin{pmatrix} x & y & z \end{pmatrix} \begin{pmatrix} A & \frac12D & \frac12 F \\ \frac12 D & B & \frac12 E \\ \frac12 F & \frac12 E & C \end{pmatrix} \begin{pmatrix} x \\y \\ z \end{pmatrix} + \begin{pmatrix} G & H & I \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} + J = \mathbf{x}^TM\mathbf{x} + \mathbf{b}^T \mathbf{x} + J = 0.[/tex] Now [itex]M[/itex] is symmetric, so its eigenvalues are real and it has a basis of orthogonal eigenvectors; thus there exists a rotation (ie. a matrix [itex]R[/itex] with determinant 1 such that [itex]R^{-1} = R^T[/itex]) such that [itex]R^{-1}MR[/itex] is diagonal. What happens if you now set [itex]\mathbf{x} = R\mathbf{X}[/itex] in the general form and complete the squares in each variable for which the corresponding diagonal entry of [itex]R^{-1}MR[/itex] is non-zero?
I will try first and update what I have done.

e_jane said:
They took out that whole chapter? Nice! I remember *hating* that chapter. :oldruck:
Can you maybe tell me the name of the chapter or anything related to the transformation of quadric surface so I can learn the basic?

Thanks
 
  • #5
e_jane said:
They took out that whole chapter? Nice! I remember *hating* that chapter. :oldruck:
songoku said:
Can you maybe tell me the name of the chapter or anything related to the transformation of quadric surface so I can learn the basic?

I sold that textbook back to the university's bookstore about thirty years ago. Sorry.
 
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