1. The problem statement, all variables and given/known data Find an equation of the plane that passes through the point (6,0,-2) and contains the line x=4-2t, y=3+5t, z=7+4t. 2. Relevant equations 3. The attempt at a solution Here's what I did: I substituted t=2 to get: x=0, y=17, z= 15 So in total, we have three points that the plane contains: P1(6,0,-2), P2(4,3,7), P3(0,17,15) Vector P1P2=<-2,3,9> Vector P1P3=<-6,17,17> I took a cross product of these vectors to get <-102,-20,-16> I used the point P1(6,0,-2) to obtain: -102(x-6)-20(y-0)-16(z+2)=0 But the solution is 33(x-6)-10(y-0)-4(z+2)=0 I'm unable to understand what I did wrong. I'd really appreciate any help!