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Julianj
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Homework Statement
If 100 grams of glass (specific heat .2 cal/g*°C) at a temperature of 500 °C is added to 20 g of 0°C water, what is the final equilibrium temperature?
Homework Equations
Q= mcΔT
The Attempt at a Solution
I know that I have to set the two equation against each other:
(100 g)*(.2 cal/g*°C)*(500°C -T) = (20 g)*(0°C+T)
20*(500-T)= 20T
10,000 - 20T= 20T
10,000 = 40T
250 = T
I have an answer of 250°C, but my answer key says that the correct answer is 100°C. Any help?? Thank you!