Finding the equivalent resistance b/w a and b

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SUMMARY

The discussion focuses on calculating the equivalent resistance between points A and B in a circuit. Key equations include the series resistance formula (Req = R1 + R2 + ... Rn) and the parallel resistance formula (Req = 1 / (1/R1 + 1/R2 + ... + 1/Rn)). The user initially struggled with identifying series and parallel configurations but found guidance in applying Kirchhoff's Rules for circuit analysis. A helpful tutorial link was shared to aid in understanding the application of these concepts.

PREREQUISITES
  • Understanding of series and parallel resistor configurations
  • Familiarity with Kirchhoff's Voltage and Current Laws
  • Basic circuit analysis skills
  • Knowledge of Ohm's Law
NEXT STEPS
  • Study Kirchhoff's Rules in detail for circuit analysis
  • Practice problems involving series and parallel resistor combinations
  • Explore advanced circuit analysis techniques using mesh and nodal analysis
  • Review tutorials on equivalent resistance calculations
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to improve their circuit analysis skills.

lgmavs41
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Homework Statement


The problem is to find the equivalent resistance between a to b.

Homework Equations


Req in series = R1 + R2 + ... Rn
Req in parallel = inverse of sum of 1/R1 + 1/R2 + ... 1/Rn
Kirchhoff's Rules

The Attempt at a Solution


Well, I tried redrawing the circuit to figure out which resistors are in parallel and which are in series but it didn't help. The 1 ohm branches off to 9 ohms and 8 ohms; 6 ohms is connected to 8 ohms which forms a series with 3 ohms...(confuses me...). Anyway, I thought I shouldn't be using the Req equations but instead will be using Kirchhoff's rules somehow. I just don't know how to apply it here in this problem. Anyone have any suggestion as to how to start solving it? Thanks in advance

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Thanks for the link. I have some idea now on how to solve it.
 

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