Finding the Equivalent Resistance of a Circuit

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Homework Help Overview

The discussion revolves around finding the equivalent resistance of an RLC circuit, specifically determining the configuration of resistors, inductors, and capacitors as either in series or parallel. The problem is set in the context of an AC circuit analysis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial assumption that the equivalent resistance is simply R4 due to no current passing through R1, R2, and R3. Others question the grounding of one point in the circuit and seek clarification on whether the problem is AC or DC. There is also a mention of using complex impedance instead of equivalent resistance for the circuit analysis.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the circuit configuration and the implications of AC analysis. Some guidance has been offered regarding the use of complex impedance and the application of Kirchhoff's loop rule, but no consensus has been reached on the correct approach.

Contextual Notes

Participants note the complexity of the problem, indicating it involves a second-order transient RLC circuit. There is mention of removing voltage and current sources to simplify the analysis, and one participant acknowledges an error regarding the grounding in the original circuit diagram.

wiz0r
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Homework Statement



I need to find the equivalent resistance of the following circuit that can be found in the attachment. Also, I need to find if the C, L and Req are in series or parallel.

Homework Equations


Rs = R1 + R2 + R3 + ... + Rn

Rp = (R1 * R2 * ... * Rn) / (R1 + R2 + ... + Rn)


The Attempt at a Solution



Okay, well, since there's no current passing through R1, R2, and R3, I assume that Req = R4. Therefore, the capacitance, inductance and the equivalent resistance are in Series.

Am I right? Or is there something wrong?

Any help will be gladly appreciated!
 

Attachments

  • resis_equiv.JPG
    resis_equiv.JPG
    17.7 KB · Views: 604
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Aren't you supposed to find the equivalent resistance between the two connectors at the top?
Having one point of the circuit grounded doesn't really make sense.
is this a DC or an AC problem, where you have to find the equivalent impedance?
 
hello, kamerling.

the problem I'm trying to solve is a little more difficult than what it seems.

it is a AC problem, more specific it is a second order transient RLC circuit.

the original circuit can be found in the attachment of this post.

the first step to solve the problem is finding if R, L and C are either in Series or Paralel. That's what I'm doing.

I remove the voltage source by a short and the current source by an open circuit, then assume the switch will be opened at t>0, so there will be an open circuit where the switch was.

after doing that, i got the circuit that i posted on my first post. so, I'm trying to find if the Req, L, and C, are in series or parallel to be able to completely solve the problem.

EDIT: The ground isn't supposed to be there, I apologize. I edited the original circuit and left it there, sorry!
 

Attachments

  • fullcircuit.JPG
    fullcircuit.JPG
    22.9 KB · Views: 466
Last edited:
I don't think that calculating an equivalent resistance is going to be much help. You can replace R3, R4, L1 and C1 with an equivalent complex impedance. L1 and R4 are in series, the resulting impedance is parallel with C1 and the result from that is in series with R3. you should be able to see that before you get to AC problems.
I rather wonder what the question is
A transient AC problem would normally involve kirchhofs loop rule and differential equations, using V = L(dI/dt) for the inductor and I = C(dV/dt) for the capacitor
 

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