Finding the final temperature of a mixture of ice and steam

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SUMMARY

The forum discussion centers on calculating the final temperature of a mixture of ice and steam, specifically addressing the heat transfer involved in the phase changes. Participants clarify that the heat relinquished by steam during condensation is a positive quantity, while the temperature change (ΔT) for steam is negative as it cools. The correct approach involves using the equation Q1 + Q2 = Q3 + Q4, ensuring all heat quantities (Q1, Q2, Q3, Q4) are treated as positive. The final temperature calculated by one participant was 42 degrees Celsius, indicating a need for careful consideration of heat flows and sign conventions in thermodynamic equations.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically heat transfer and phase changes.
  • Familiarity with the concepts of latent heat of vaporization and fusion.
  • Knowledge of the specific heat capacity of water and ice.
  • Ability to manipulate and solve equations involving heat transfer (Q = mcΔT).
NEXT STEPS
  • Study the principles of latent heat and its application in phase changes.
  • Learn about the specific heat capacities of different states of water (ice, liquid, steam).
  • Explore thermodynamic equations and their applications in heat transfer problems.
  • Practice solving problems involving mixtures of different phases and the associated energy transfers.
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, educators teaching heat transfer concepts, and anyone involved in physics or engineering fields requiring a solid understanding of energy conservation in phase changes.

  • #31
To @ayans2495:
Something that might save you from future grief is the good habit of using different subscripts for different entities. The default is that the same symbol with the same subscript is the same quantity. In posting #1 you say
miceLf + micecw ΔT= msteamLv + msteamcwΔT
I would use different subscripts to distinguish the two different changes in temperature, and then replace in the next equation ΔTice = Tf - Tice and ΔTsteam = Tf - Tsteam where Tice = 0 oC and Tsteam = 100 oC.
 
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  • #32
Noted. Thank you!
 

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