Finding the Function f(x) Given Certain Conditions

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The discussion centers on finding the differentiable function f(x) that satisfies the equation f(x)f(y) + 2 = f(x) + f(y) + f(xy), with the conditions f'(0) = 0 and f'(1) = 2. Participants attempted to derive a differential equation by differentiating the given equation with respect to x and substituting y = x, leading to the equation 2f(x)f'(x) = 2f'(x) + f'(x^2)2x. The challenge lies in expressing f'(x^2)2x in terms of dy/dx for further analysis.

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  • Understanding of differentiable functions and their properties
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  • Knowledge of implicit differentiation techniques
  • Basic calculus concepts, including derivatives and function behavior
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Mathematics students, educators, and anyone interested in advanced calculus and differential equations will benefit from this discussion.

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1. If f(x) be a differentiable function, such that f(x)f(y) + 2 = f(x) + f(y) + f(xy); f'(0) = 0 & f'(1) = 2, then find f(x).



Homework Equations





The Attempt at a Solution


I tried differentiating the given stuff wrt to x and then tried to put in the values given instead of y and find a differential equations by solving which I could get the function.. That didn't work with the stuff tried. Then I went on to substitute y=x and tried to get a differential equation. But I was unable to write f'(x^2)2x in terms of dy/dx.. So, I couldn't go ahead. Also, was it mathematically correct to put in x=y to solve the question?
 
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root_two said:
1. If f(x) be a differentiable function, such that f(x)f(y) + 2 = f(x) + f(y) + f(xy); f'(0) = 0 & f'(1) = 2, then find f(x).



Homework Equations





The Attempt at a Solution


I tried differentiating the given stuff wrt to x and then tried to put in the values given instead of y and find a differential equations by solving which I could get the function.. That didn't work with the stuff tried. Then I went on to substitute y=x and tried to get a differential equation. But I was unable to write f'(x^2)2x in terms of dy/dx.. So, I couldn't go ahead. Also, was it mathematically correct to put in x=y to solve the question?
What did you get when you differentiated?

Yes, it was mathematically correct to put in x=y to help solve this.
 
Well actually on differentiating I am getting this:
2f(x)f'(x) = 2f'(x) + f'(x^2)2x

Now I can put f'(x) as dy/dx but what do I do with f'(x^2)2x??
 

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