MHB Finding the function of a maclaurin series

Click For Summary
The discussion focuses on determining the function represented by a specific Maclaurin series. The series starts with 1 and includes alternating terms involving odd powers of x and factorial denominators. It is derived into a sigma notation, which leads to the conclusion that the series can be expressed as 1 plus a summation involving sine. The final result indicates that the function corresponding to the series is sin(5x) - 5x + 1. This highlights the relationship between Maclaurin series and trigonometric functions.
tmt1
Messages
230
Reaction score
0
I need to find the function for this Maclaurin series

$$1 - \frac{5^3x^3}{3!} + \frac{5^5x^5}{5!} - \frac{5^7x^7}{7!} ...$$

I can derive this sigma:

$$1 + \sum_{n = 2}^{\infty} \frac{(-1)^{n - 1} 5^{2n - 1} x^{2n - 1}}{(2n - 1)!}$$

But I'm not sure how to get this function from this series.
 
Physics news on Phys.org
The sum may be written as

$$1+\sum_{n=1}^\infty\dfrac{(-1)^n}{(2n+1)!}(5x)^{2n+1}$$

which is equivalent to $\sin(5x)-5x+1$.

See here for a summary of some well-known MacLaurin series.
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K