Finding the General Solution for a Second Order Differential Equation

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The discussion centers around a second-order differential equation presented by a user, which they have partially solved, identifying a specific solution as y(x) = cosh(x + C1). However, they acknowledge the existence of a more general solution due to the equation's second-order nature, which should have two degrees of freedom. Another participant requests that the original poster share their methods or attempts at finding the general solution, emphasizing the need for a more detailed approach rather than simply asking for help. The conversation highlights the importance of demonstrating one's work in mathematical discussions to facilitate better assistance.
Daniel D
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Hi,

I came across the following differential equation:

\sqrt{1+(y')^2}=\frac{d}{dx}\left(y\frac{y'}{\sqrt{1+(y')^2}}\right)

I found possible solutions: y\left(x\right)=cosh(x+C_{1}).
However, this is a second order ODE so there exist a more general solution, with 2 freedom degrees.

Can anyone find it?

Thank you.
 
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Daniel D said:
Hi,

I came across the following differential equation:

\sqrt{1+(y')^2}=\frac{d}{dx}\left(y\frac{y'}{\sqrt{1+(y')^2}}\right)

I found possible solutions: y\left(x\right)=cosh(x+C_{1}).
However, this is a second order ODE so there exist a more general solution, with 2 freedom degrees.

Can anyone find it?

Thank you.

What do you mean "can anyone find it"? Please show us how you have tried to find it so far. This is the PF, not Yahoo answers.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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