Finding the green's function for a second order linear DE and solve it

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SUMMARY

This discussion centers on the application of Green's functions to solve second-order linear differential equations, specifically the equation \(\frac{d^2 y(x)}{d x^2} - a^2 y(x) = e^{-t}\) with boundary conditions \(y(0)=0\) and \(y'(0)=0\). The original poster, David, expressed confusion regarding the non-standard boundary conditions, which differ from typical cases found in literature. Ultimately, David resolved the issue, noting that most Green's function problems indeed adhere to the boundary conditions \(y(0)=0\) and \(y(L)=0\).

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  • Understanding of Green's functions in differential equations
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  • Knowledge of boundary value problems
  • Basic calculus and differential equations
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  • Learn about self-adjoint operators in the context of differential equations
  • Explore specific examples of Green's functions applied to non-standard boundary conditions
  • Investigate the implications of different boundary conditions on the solutions of differential equations
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storluffarn
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Homework Statement



So I'm trying to get a grip about those Green functions and how to aply them to solve differential equations. I've searched the forums and read the section on green's functions in my course book both once and twice, and I think I start to understand at least som of it. However, all the cases treated in the litterature and most problems I found on the forums had boundary conditions on the form y(a)=q, y(b)=q. In the problem bellow I do not have these kind of boundary conditions.

"Construct the Green's function and apply it to solve the differential equation

\frac{d^2 y(x)}{d x^2} -a^2 y(x) = e^{-t}

subject to the boundary conditions y(0)=0, y'(0)=0

My question is this:

What do I do when the boundary conditions is in this form?

Homework Equations



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The Attempt at a Solution



Well, I tried to see the situation as if y was bounded in the interval 0 to infinity, but that didn't work out to good. I also tried to formulate the equaton as a self adjoint, but that to failed.

Cheeres,
David
 
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Nvm, problem solved, thanks anyway!
 
Actually, that was a very strange question! All "Green's function" problems have those boundary conditions: y(0)= 0, y(L)= 0.
 

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