Finding the horizontal asymptote

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To find the horizontal asymptote for the function f(x) = xe^(-x^2), analyze the behavior as x approaches large positive and negative values. As x becomes very large and positive, the term e^(-x^2) dominates, causing f(x) to approach 0, indicating that y = 0 is a horizontal asymptote. For large negative values of x, both x and e^(-x^2) do not converge to a limit, meaning there is no horizontal asymptote in that direction. The analysis shows that while there is a horizontal asymptote at y = 0 for positive x, none exists for negative x. Understanding these limits is crucial for determining horizontal asymptotes in functions.
alpha01
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How do i find the horizontal asymptote for f(x)=xe-x2

thanks for the help.
 
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The same way you find a horizontal asymptote, if it exists, for any function: look at what happens for very large (positive or negative) values of x. If x is a very large positive number the e-x2 "dominates": xe-x2 goes to 0 so 0 is a horizontal asymptote. You can get the idea, though it is not a proof, by looking at, say, x= 1000: (1000)e-1000000= very close to 0. For x a very large negative number, both x and e-x2- there is no horizontal asymptote in that direction.
 
thanks
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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