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Getting the Horizontal Asymptotes

  1. Dec 12, 2017 #1
    1. The problem statement, all variables and given/known data
    upload_2017-12-12_21-42-30.png

    2. Relevant equations


    3. The attempt at a solution
    I understand there is no vertical asymptotes and can usually get the horizontal ,but can't understand with the exponential.
     
  2. jcsd
  3. Dec 12, 2017 #2

    Ray Vickson

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    Your image is fuzzy and unreadable. Take the trouble to actually type out the problem---that is actually the PF preferred standard!
     
  4. Dec 12, 2017 #3
    Noted :) , here goes:

    f(x)=1/1+e3x
     
  5. Dec 12, 2017 #4
    Try graphing it, and then go from there.
     
  6. Dec 12, 2017 #5

    SammyS

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    You should enclose that denominator in parentheses.
    f(x)=1/(1+e3x)​

    What happens to e3x as x gets very large ?

    What happens to e3x as x gets very negative ?
     
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