Getting the Horizontal Asymptotes

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Homework Help Overview

The discussion revolves around understanding horizontal asymptotes in the context of a function involving an exponential term, specifically f(x) = 1/(1 + e^(3x)). Participants are exploring the behavior of this function as x approaches large positive and negative values.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the absence of vertical asymptotes and express confusion regarding horizontal asymptotes related to the exponential function. There are suggestions to graph the function and inquiries about the behavior of the exponential term as x varies.

Discussion Status

Some guidance has been offered regarding graphing the function and considering the limits of the exponential term. Participants are actively questioning the implications of the function's structure on its asymptotic behavior.

Contextual Notes

There is mention of a preference for typed problems over images, indicating a focus on clarity in communication. The discussion also highlights the need to consider the function's behavior at extreme values of x.

MatthewR

Homework Statement


upload_2017-12-12_21-42-30.png


Homework Equations

The Attempt at a Solution


I understand there is no vertical asymptotes and can usually get the horizontal ,but can't understand with the exponential.
 

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MatthewR said:

Homework Statement


View attachment 216624

Homework Equations

The Attempt at a Solution


I understand there is no vertical asymptotes and can usually get the horizontal ,but can't understand with the exponential.

Your image is fuzzy and unreadable. Take the trouble to actually type out the problem---that is actually the PF preferred standard!
 
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Ray Vickson said:
Your image is fuzzy and unreadable. Take the trouble to actually type out the problem---that is actually the PF preferred standard!
Noted :) , here goes:

f(x)=1/1+e3x
 
Try graphing it, and then go from there.
 
MatthewR said:
Noted :) , here goes:

f(x)=1/1+e3x
You should enclose that denominator in parentheses.
f(x)=1/(1+e3x)​

What happens to e3x as x gets very large ?

What happens to e3x as x gets very negative ?
 

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