Finding the impulse of a hockey puck colliding with a wall

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SUMMARY

The discussion focuses on calculating the impulse experienced by a hockey puck during a collision with a wall. A 261 g hockey puck traveling at 5.34 m/s collides at an angle of 27.3° and rebounds with the same speed and angle. The impulse is derived using the equation J = m*∆Vy, resulting in a magnitude of 2.306 kg*m/s. The average force exerted by the puck on the wall can be calculated using the impulse and the contact time of 10.9 ms, though the correct impulse value is essential for this calculation.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Familiarity with vector components in physics
  • Knowledge of basic trigonometry for angle calculations
  • Proficiency in using the equations J = F*∆t and p = m*v
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  • Review the concept of impulse and its relation to momentum
  • Learn about vector decomposition in two-dimensional collisions
  • Study the effects of contact time on average force calculations
  • Explore the significance of angle measurements in collision physics
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Students studying physics, particularly those focusing on mechanics and collision analysis, as well as educators seeking to clarify impulse and momentum concepts in practical scenarios.

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Homework Statement



A 261 g hockey puck is sliding on ice with a speed of 5.34 m/s hits a wall at an angle of 27.3° to the wall and bounces back at the same angle with the same speed.

a) If the wall and the hockey puck are in contact for 10.9 ms, find the magnitude of the impulse on the puck.
b) Calculate the average force exerted by the puck on the wall.

Homework Equations


J = F*∆t = ∆p
p = m*v
a = ∆v/∆t

The Attempt at a Solution



a) I assumed that velocity in the x is not changing, and thus ∆Vx = ∆px = 0. Based on that, I assumed that any impulse/change in momentum, can be calculated from the y-component.

Jy = J = m*∆Vy
= m(Vfy - Viy) _____ Viy = -Vfy
= m (2Vfy)
=2*m*Vfy = (2)(0.261)(5.34 sin 27.3)
J = 2.306 kg*m/s

however, it says that this answer is incorrect. I'm not sure where I'm going wrong, as only the initial and final velocities in the y are changing, and thus Jy = J.

b) I'm assuming that the average force can be calculated via J = F*∆t, as i don't have the correct magnitude of the impulse yet, I haven't been able to calculate it correctly
 
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Check your calculator for the degree/radian setting!
 
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