Finding the intersection of a plane

  • Thread starter Thread starter clickcaptain
  • Start date Start date
  • Tags Tags
    Intersection Plane
Click For Summary
To find the intersection of the plane with the moment vector M = Ta(4i - 3j), the discussion centers on visualizing the moment's direction and its relation to the y-z plane. The user suggests setting x=0 to simplify the problem, indicating a focus on the y-z plane where the moment acts. Clarification is sought on whether the moment aligns with the pole's intersection with the plane. The conversation highlights the need for a clearer understanding of the moment's orientation in relation to the forces acting on the pole. Overall, the discussion emphasizes the importance of visualizing the mechanics involved in the problem.
clickcaptain
Messages
31
Reaction score
0
Here is the problem:

Replace the two forces afting on the pole by a wrench. Write a moment M associated with a wrench as a vector and specify the coordinates of the point P in the y-z plane through which the line of action of wrench passes.

I already figured the moment to be
("T" and "a" are both scalar)

M = Ta(4i - 3j)

How would I go about finding the intersection of the plane? My train of thought is leading me towards the idea that I need to set x=0 but I'm not sure...

thanks for the help in advance!
 
Physics news on Phys.org
clickcaptain said:
Replace the two forces afting on the pole by a wrench. Write a moment M associated with a wrench as a vector and specify the coordinates of the point P in the y-z plane through which the line of action of wrench passes.

I already figured the moment to be
("T" and "a" are both scalar)

M = Ta(4i - 3j)

How would I go about finding the intersection of the plane? My train of thought is leading me towards the idea that I need to set x=0 but I'm not sure...

Hi clickcaptain! :smile:

I can't quite visualise this …

doesn't the moment go along the pole, to where the pole meets the y-z plane? :confused:

If I'm wrong, perhaps you'd better give us more details. :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K