Finding the Inverse Laplace of F(s)

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SUMMARY

The discussion focuses on finding the inverse Laplace transform of the function F(s) = (s^2 + 1) / (s^2 + 4s + 3). The user correctly identifies that long division is necessary due to the degree of the numerator being equal to that of the denominator, resulting in F(s) = (-4s - 2) / ((s + 1)(s + 3)) + 1. The user successfully computes the inverse Laplace transform for the first term but seeks assistance with L^-1{1}, which is identified as the Dirac delta function.

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Homework Statement


[tex]F(s) = \frac{s^2 + 1}{s^2 + 4s + 3}[/tex]
Find the inverse laplace transform?

The Attempt at a Solution


Since the nominator's degree is not smaller that the denominator, i have to do the long division before doing the inverse laplace.

[tex]F(s) = \frac{- 4s - 2}{(s+1)(s+3)} + 1[/tex]

I can get the inverse laplace for the first term. However, I was stopped at L-1{1}. Need help. Thank you.
 
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Hint: What is [tex]\int_{0^-}^{\infty} \delta (t) e^{-st}dt[/tex] ? (where [itex]\delta[/itex] is the dirac delta function)
 
L-1{1}=diracdelta
 

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