Finding the kinetic energy of an electron

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SUMMARY

The kinetic energy (KE) of an electron moving in a spiral path is calculated using the formula KE = (1/2)Iω² = (1/2)mr²ω², where 'm' is the mass of the electron, 'r' is the radius, and 'ω' is the angular velocity. In this case, the position of the electron is defined by r(t) = r(0) + c1*t and θ(t) = θ(0) + c2*t, with constants r(0), c1, θ(0), and c2. The correct kinetic energy expression is KE = (1/2)(m)(c1² + r²c2²), indicating that the initial attempt at solving the problem miscalculated the radius and angular velocity.

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texan14
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Homework Statement



An electron's position is given by r(t)=r(0)+c1*t, θ(t)=θ(0)+c2*t, where r(0), c1, θ(0), and c2 are known constants. What is the kinetic energy of the electron? (mass=m)

Homework Equations



KE=(1/2)Iω2=(1/2)mr2ω2

The Attempt at a Solution



plugging in m for mass, r(0)+c1*t for radius, and c2 for ω
(1/2)(m)(r(0)+c1*t)2(c2)2

This isn't the correct answer, so I'm fairly certain I've messed up on my "r" value somehow.

It's supposed to equal (1/2)(m)(c12+r2c22)

Where am I going wrong?
 
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hi texan14! :smile:
texan14 said:
An electron's position is given by r(t)=r(0)+c1*t, θ(t)=θ(0)+c2*t, where r(0), c1, θ(0), and c2 are known constants. What is the kinetic energy of the electron? (mass=m)

KE=(1/2)Iω2=(1/2)mr2ω2

what on Earth are you doing? :confused:

that's for a rigid body with angular velocity ω

this is a spiral … you have no idea what ω(t) is, it certainly isn't θ'

start again, and just use v = (r',rθ') :smile:

(you do know how to prove that, don't you? … if you don't, then look it up)
 

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