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Finding the length of the curve

  1. Apr 6, 2013 #1
    find the curve at the point (-8,1) that gives the integrals length in the picture posted

    i literally have no clue what to do. am i supposed to take the derivative of 16/y^3 and square it?

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  2. jcsd
  3. Apr 6, 2013 #2


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    Well, no. The 16/y^3 should be (x')^2 for one of those functions. Which one is it?
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