Finding the length of the curve

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SUMMARY

The discussion focuses on finding the length of a curve at the point (-8, 1) using calculus. Participants clarify that the expression 16/y^3 should be interpreted as (x')^2, indicating a misunderstanding in the initial approach. The correct method involves applying the arc length formula, which requires the derivative of the function representing the curve. The conversation emphasizes the importance of correctly identifying the function to derive the necessary components for calculating the curve's length.

PREREQUISITES
  • Understanding of calculus, specifically derivatives and integrals.
  • Familiarity with the arc length formula in calculus.
  • Knowledge of implicit differentiation and its application.
  • Basic graphing skills to visualize curves and points.
NEXT STEPS
  • Study the arc length formula in calculus, specifically for parametric equations.
  • Learn about implicit differentiation and its applications in curve analysis.
  • Practice finding derivatives of functions to prepare for arc length calculations.
  • Explore examples of curve length problems to solidify understanding of the concepts.
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in understanding curve length calculations and their applications in real-world scenarios.

billsauce
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find the curve at the point (-8,1) that gives the integrals length in the picture posted

i literally have no clue what to do. am i supposed to take the derivative of 16/y^3 and square it?
 

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billsauce said:
find the curve at the point (-8,1) that gives the integrals length in the picture posted

i literally have no clue what to do. am i supposed to take the derivative of 16/y^3 and square it?

Well, no. The 16/y^3 should be (x')^2 for one of those functions. Which one is it?
 

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