I'm stuck on this limit function and I don't know what to do next. Please help me out. Thanks!(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\lim_{x\rightarrow 0^{+}}(\frac{\csc2x}{x})[/tex]

I just turned csc2x into 1\sin2x so then I have:

[tex] \lim_{x\rightarrow 0^{+}} (\frac{1}{x\sin2x})[/tex]

Then I used the trig identity: sin2x=2sinxcosx

...but I'm not sure if this is going to take me anywhere.

I know that [tex]\lim_{x\rightarrow c} \sin x = \sin c[/tex] but I'm not sure how to incoporate that identity in this problem.

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# Finding the limit of a trig function

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