Finding the Limit of x*sin(1/x) using L'Hopital's Rule

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Homework Help Overview

The discussion revolves around evaluating the limit of the expression \( \lim_{x\rightarrow0}x\sin (\frac{1}{x}) \). The subject area is calculus, specifically focusing on limits and the application of L'Hôpital's Rule.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply L'Hôpital's Rule by rewriting the limit as \( \lim_{x\rightarrow0}\frac{\sin(\frac{1}{x})}{\frac{1}{x}} \). Some participants question whether this form is appropriate for applying the rule, noting that it does not yield a 0/0 or infinity/infinity form. Others introduce the sandwich theorem as a potential method for evaluating the limit.

Discussion Status

Participants are exploring different interpretations of the limit and discussing the applicability of various methods, including L'Hôpital's Rule and the sandwich theorem. There is a recognition of the oscillatory nature of the function involved and its implications for the limit as \( x \) approaches zero.

Contextual Notes

Some participants express a lack of familiarity with the sandwich theorem, indicating a learning moment in the discussion. There is also a sentiment that L'Hôpital's Rule is not the only method available for solving limit problems.

PhysicoRaj
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Homework Statement



Evaluate: \displaystyle\lim_{x\rightarrow0}x\sin (\frac{1}{x})

Homework Equations



L'H\hat{o}pital's~rule (?)

The Attempt at a Solution



Taking the x to denominator as \displaystyle\lim_{x\rightarrow0}\frac{\sin(\frac{1}{x})}{\frac{1}{x}} and Applying L'Hopital's rule I get \displaystyle\lim_{x\rightarrow0}\cos {\frac{1}{x}}
Have I done right? How should I proceed? Thanks.
 
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To apply l'hospital's rule, you need to put the expression in form so you get 0/0 or infinity/infinity when you apply the limit directly.

You did not manage to do that - applying the limit directly to the rearranged equation shows form "oscillating/infinity".

Do you know the sandwich theorem?
http://www.math.washington.edu/~conroy/general/sin1overx/
 
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-1\le sin(1/x)\le 1 so -x\le x sin(1/x)\le x.
 
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Thanks Simon and HallsofIvy, I understand like this: The function xsin(1/x) oscillates b/n x and -x, and as x approaches zero (left or from right), x and -x approach zero. Hence the function, which is sandwiched between these two MUST also approach zero. (I didn't know the sandwich theorem, I learned it now. Thanks :smile:)
This is one more evidence that L'Hopital's rule is not the king. Maybe I needed a more graphical, more practical view.
 
L'Hopital's rule is not the sole monarch of differential calculus, no. Before I started on PF I didn't even know the approach had a special name... none of my teachers formally taught it but we all knew the principle as part of the general behavior of limits.

As you advance you will learn many other rules and theorems. Together they form a "toolkit" that will help you work out what to do with specific problems. When you get good, you will end up facing problems where there is no known solution and you are the one who has to come up with the method. Enjoy.
 
Simon Bridge said:
L'Hopital's rule is not the sole monarch of differential calculus, no. Before I started on PF I didn't even know the approach had a special name... none of my teachers formally taught it but we all knew the principle as part of the general behavior of limits.

As you advance you will learn many other rules and theorems. Together they form a "toolkit" that will help you work out what to do with specific problems. When you get good, you will end up facing problems where there is no known solution and you are the one who has to come up with the method. Enjoy.

Then I would really like it. :!) Maybe this is why 'math' is the 'science' of numbers. :cool:
 
That's the spirit - enjoy :)
 

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