Finding the Linear Equation Relating Price and Number of Widgets Sold

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The discussion focuses on deriving a linear equation that relates the price of widgets (x) to the number of widgets sold per day (y). Given the price points of $2 for 300 widgets and $4 for 200 widgets, participants confirm the use of the slope formula, m = Δy/Δx, to calculate the slope and subsequently apply the point-slope formula to find the linear equation in the form y = mx + b. The two equations derived from the points (2, 300) and (4, 200) allow for the calculation of the coefficients a and b, confirming the linear relationship between price and sales.

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woof123
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Okay here's the question:

If you sell widgets for 2 dollars, you sell 300 per day. If you sell them for 4 dollars, you sell 200 per day. assume linear relat., between price (x) and # widgets sold per day (y), write linear equation relating x and y

I'm thinking I plot the x,y pairs, then calculate slope and the y intercept in order to put it into y=mx+b form...does that make sense?
 
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You have two points on the graph, so you can compute the slope as follows:

$$m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}$$

Then, you can use either point (I'll use the first), and the slope you computed, in the point-slope formula:

$$y=m(x-x_1)+y_1$$ :D
 
Equivalently, any linear function can be written y= ax+ b for numbers a and b. The fact that y(2)= 300 means that 2a+ b= 300. The fact that y(4)= 200 means that 4a+ b= 200. Solve those two equations for a and b.

(An obvious point is that there is "b" with coefficient 1 in both equations. Subtracting one equation from the other eliminates b leaving a single equation for a. Do you see that this is the same as your formula for slope? And then using that value of a in one of the two equations to find b is the same as MarkFL suggests.)
 

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