Finding the magnetic field strength

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SUMMARY

The discussion centers on calculating the magnetic field strength at the origin due to a current of 5A flowing in the y-direction at coordinates (2m, 0, -2m). The magnetic field strength is derived using the formula B = (μI/2πR) * r, where R is the distance from the origin, calculated as r = √(2^2 + 2^2) = 2√2 m. The final magnetic field strength is determined to be B = 5 * 10^-7 T. Participants clarify the correct application of the distance formula and the distinction between magnetic induction and magnetic field strength.

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  • Understanding of Ampere's Law
  • Familiarity with magnetic field equations
  • Knowledge of vector mathematics
  • Basic principles of electromagnetism
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johndough999
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Homework Statement


There exists a current of 5A in the ay direction at x=2m,z=-2m where the ay is the unit vector in the y direction. Find the magnetic field strength at the origin.

Homework Equations


B = (μI/2πR) * r
B = μH

The Attempt at a Solution


B = (μI/2πr)
B= (4π*10^-7)(5)/2π(2)
where r is the distance from origin, in this case r=2m.
B=5*10^-7 T

I believe I am not finding the correct distance from the origin.Not using the z axis at all.
Thanks for the help!
 
Last edited:
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Amperes law:

Cirkulation ∫ Hds = N * I →

H = I / (2πr)

r = √(22+22) (pythagoras).

You should not find B, as it is the magnetic induction (flux-density).
 
Last edited:
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Hi Hesch, to find the distance from the origin are you using the following formula?
√ X^2 + Y^2 + Z^2
 
No, I'm using r = √(x2+z2)

Plot the locations of the conductor and the origin in the plane: y = 0.
 
Thanks for the help hesch!
 

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