Finding the magnitude of acceleration in 2D motion

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SUMMARY

The discussion focuses on calculating the magnitude of average acceleration for a car transitioning from a southward velocity of 20.0 m/s to a westward velocity of 29.0 m/s over a time interval of 20.7 seconds. The correct approach involves determining the change in velocity using the Pythagorean theorem, resulting in a resultant velocity of 35.2 m/s. The average acceleration is then calculated by dividing this change in velocity by the time interval, yielding an average acceleration of 1.7 m/s². Key clarifications emphasize that the magnitude of average acceleration is distinct from the change in speed.

PREREQUISITES
  • Understanding of 2D motion and vector components
  • Familiarity with the Pythagorean theorem for calculating resultant velocity
  • Knowledge of average acceleration formula: average a = change in velocity / change in time
  • Basic proficiency in unit conversion and dimensional analysis
NEXT STEPS
  • Study vector addition in 2D motion scenarios
  • Learn about the implications of direction on average acceleration calculations
  • Explore examples of average acceleration in real-world applications
  • Review kinematic equations for motion in two dimensions
USEFUL FOR

Students in physics, particularly those studying kinematics, as well as educators seeking to clarify concepts related to acceleration in two-dimensional motion.

Dano1337
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Homework Statement


A car moving due south at 20.0 m/s enters a highway cloverleaf. The car will exit the cloverleaf to merge with westbound traffic traveling at 29.0 m/s.

The time between entering the cloverleaf and exiting to merge with westbound traffic is 20.7 s. What is the magnitude of the average acceleration of the car?

For the units, use a ^ to indicate an exponent.

Your answer should have one digit after the decimal place.

Homework Equations


magnitude eq = v = sqrt (x^2)+(y^2)
average a = change in velocity / change in time

The Attempt at a Solution


1. sqrt ((20^2)+ ((29^2)) = 35.2 m/s
2. 35.2 / 20.7 = 1.7 s
any help or advice on where I'm going wrong would be very much appreciated. [/B]
 
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Check the units on your last line (2)?
 
Dano1337 said:
average a = change in velocity / change in time
Correct.
Dano1337 said:
magnitude eq = v = sqrt (x^2)+(y^2)
It says nothing about change in speed.
Dano1337 said:
magnitude of the average acceleration
Magnitude of change of velocity is not the same as change of magnitude of velocity.
 

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