Finding the mass of iron using the heat equations

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    Heat Iron Mass
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Homework Help Overview

The discussion revolves around calculating the mass of iron that causes a specific temperature change in water, utilizing heat transfer equations. The problem involves understanding the relationship between the heat gained by water and the heat lost by iron.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the heat transfer equation and question the final temperature of the iron. There is a focus on how to determine the temperature change of the iron without its mass being provided.

Discussion Status

The discussion is ongoing, with participants raising questions about the necessary information to solve the problem. Some guidance is offered regarding the principles of thermal equilibrium, but no consensus has been reached on how to proceed without additional data.

Contextual Notes

There is a noted lack of information regarding the final temperature of the iron, which is critical for solving the problem. Participants are grappling with the implications of this missing data on their calculations.

math989
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Homework Statement


Calculate themass of iron at 100C that causes 20.0 kg of water to change temperature from 16C to 18C. C of iron is 460 J/kg C. The C for water is 4190. [/B]

Homework Equations


q1+q2=0
q=mct[/B]

The Attempt at a Solution


q1=-q2
mct=-mct
20(4190)(2)=-m(460)(100)
167600=46000m
3.5=m
 
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What's the final temperature of the iron? What was the temperature change of the iron?

Chet
 
That's my main issue right now because that is not given to me and I am having a hard time trying to figure how one would do that without the mass being given.
 
math989 said:
That's my main issue right now because that is not given to me and I am having a hard time trying to figure how one would do that without the mass being given.
If you put something hot in contact with something cold and let them equilibrate with one another, do they (a) reach different final temperatures or (b) reach the same final temperature?

Chet
 

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