(adsbygoogle = window.adsbygoogle || []).push({}); QUESTION:An archer shoots an arrow straight up in the air with an initial velocity of 45 m/s , it takes the arrow 4.6 s to reach its maximum height. Calculate this maximum height.

the α, ∆d, and vi should have arrows over them:

MY ANSWER:

displacement = ½ [(α ∙ ∆t + vi) + vi + vi] ∆t

therefore vi ∆t + ½ α t(2)

therefore ∆d = 207 + 103.68

therefore ∆d = 310.68 m

I'm not sure if i used the correct formula or if my answer if right.

Also, how do you draw vector diagrams to scale? :shy:

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# Finding the maximum height of an arrow shot in the air

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