(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A harmonic oscillator with a vertical mass on a string has a hanging mass of 2m and a spring constant of K. It oscillates with an amplitude of Z. When its position is at a distance Z/2 of the equilibrium point, its potential energy is U_{i}. What is the maximum kinetic energy K_{m}?

2. Relevant equations

E=1/2mV^{2}+ 1/2mA^{2}

3. The attempt at a solution

I realized that the max kinetic energy must be equal to the to the max potential energy because total energy is constant. I just don't know where to put the equations to make it fit.

Can someone show me the set up? The answer give was K_{m}= 4U_{i}

Thanks in advance!

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# Homework Help: Finding the maximum kinetic energy of a harmonic oscillator

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