Finding the Maximum Mass Ratio for Elastic Collisions: A Quick Homework Problem

AI Thread Summary
The discussion centers on a homework problem involving elastic collisions between two objects of mass M and a smaller mass m. The user successfully applies the laws of conservation of energy and momentum to derive the post-collision velocities of both masses. The calculated velocities are v1 for mass m after colliding with B and v2 for mass B after the collision. The final result determines the maximum mass ratio M/m, ensuring that the velocity of m remains less than or equal to that of B, yielding a ratio of 2 + √5. The solution appears to be correct based on the calculations presented.
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Homework Statement


IMG_20171225_053813~2.jpg

Both object A and B have mass M and are moving.
An object with mass of m and moving with velocity u collide with the object B elastically. (m < M)
Find the following after m collide with B
1) Velocity of m after bouncing back
2) Velocity of B
Then m collide with A and bounce back
3) The highest value of M/m that velocity of m is lesser than or equal to that of B
(Surface has no friction)

Homework Equations

The Attempt at a Solution


Using the Law of Energy Conservation and the Law of Momentum Conservation

##\frac{1}{2} m u^2 = \frac{1}{2} m v_1^2 + \frac{1}{2} M v_2^2##

##m u = -m v_1 + Mv_2##

After solving the equation, I get this

##v_1 = \frac{M - m}{M + m} u## (Answer for (1))

##v_2 = \frac{2 m}{M + m} u## (Answer for (2))

Then object m hit object A. The velocity of m then change into

##(\frac{M - m}{m + M})^2 u##

Velocity of m should be equal to that of B so m cannot reach B

##(\frac{M - m}{m + M})^2 u = \frac{2 m u}{m + M}##

##\frac{M}{m} = 2 + \sqrt{5}## (Answer for (3))

Is that correct?
 

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Looks fine.
 
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