- #1

- 110

- 4

- Homework Statement:
- The graph is a separate image (it didn't print with the worksheet for some reason). I filled in the blanks, but I wasn't sure how to approach part b)

- Relevant Equations:
- n/a

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- Thread starter ttpp1124
- Start date

- #1

- 110

- 4

- Homework Statement:
- The graph is a separate image (it didn't print with the worksheet for some reason). I filled in the blanks, but I wasn't sure how to approach part b)

- Relevant Equations:
- n/a

- #2

- 989

- 80

I filled in the blanks, but I wasn't sure how to approach part b)

I should think that you can find the meaning of that expression in your calculus book. As for the value, you will probably need to review limits in order to evaluate it properly.

- #3

FactChecker

Science Advisor

Gold Member

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- #4

- 21

- 1

I suggest you look up "derivatives and sharp turns" for the meaning and value at x= -2.

- #5

Mark44

Mentor

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Correct, but please don't start a new thread for the same question. I have deleted the new thread.ttpp1124 said:My answer for 12b:

If the limit exists, it’s the derivative of 𝑓 at 𝑥=−2. But, the limit doesn’t exist. To see this, calculate the one-sided limits as h approaches zero from the right, and from the left. They both exist, but they are not the same, so the limit does not exist, meaning 𝑓 is not differentiable at 𝑥=−2

- #6

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I worry that perhaps they meant to write h→0^{+}. Or maybe that's the trap you avoided.

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