Finding the MME for p of Bin(n,p)

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SUMMARY

The discussion focuses on finding the Method of Moments Estimator (MME) for the parameter p in a Binomial distribution Bin(n, p). The key equations used include E[X] = n⋅p and Var[X] = n⋅p⋅(1-p). The estimator is derived using the sample mean \bar{X} and involves calculations of E[\bar{X}] and Var(\bar{X}). The final estimator is expressed as \hat{p} = ((\bar{X})² + \bar{X} - \bar{X}²) / \bar{X>.

PREREQUISITES
  • Understanding of Binomial distribution properties
  • Familiarity with Method of Moments Estimation
  • Knowledge of expected value and variance calculations
  • Ability to manipulate algebraic expressions involving statistical estimators
NEXT STEPS
  • Study the derivation of the Method of Moments Estimator for different distributions
  • Learn about Maximum Likelihood Estimation (MLE) and its comparison with MME
  • Explore the implications of sample size on the accuracy of estimators
  • Investigate the properties of estimators, including bias and consistency
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Statisticians, data analysts, and students studying statistical estimation methods, particularly those focusing on Binomial distributions and the Method of Moments.

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Homework Statement



X1,X2,...,Xk ~iid Bin(n,p) find the MME (Method of Moments Estimator) for p

Homework Equations



E[X] = n⋅p
Var[X] = n⋅p⋅(1-p)

Var(X) = E[X2] - [E[X]]2

The Attempt at a Solution



Does this look correct?

n⋅p⋅(1-p) = E[X2] - n2⋅p2

E[X2] = n⋅p⋅(1-p) + n2⋅p2

[itex]\bar{X}[/itex]=n⋅p

[itex]\bar{X}[/itex]2 = n⋅p⋅(1-p) + n2⋅p2

[itex]\bar{X}[/itex]2 = [itex]\bar{X}[/itex]⋅(1-p) + [itex]\bar{X}[/itex]⋅[itex]\bar{X}[/itex]

[itex]\hat{p}[/itex] = (([itex]\bar{X}[/itex])2 + [itex]\bar{X}[/itex] - [itex]\bar{X}[/itex]2) / [itex]\bar{X}[/itex]

Thanks.
 
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thesandbox said:

Homework Statement



X1,X2,...,Xk ~iid Bin(n,p) find the MME for p

Homework Equations



E[X] = n⋅p
Var[X] = n⋅p⋅(1-p)

Var(X) = E[X2] - [E[X]]2

The Attempt at a Solution



Does this look correct?

n⋅p⋅(1-p) = E[X2] - n2⋅p2

E[X2] = n⋅p⋅(1-p) + n2⋅p2

[itex]\bar{X}[/itex]=n⋅p

[itex]\bar{X}[/itex]2 = n⋅p⋅(1-p) + n2⋅p2

[itex]\bar{X}[/itex]2 = [itex]\bar{X}[/itex]⋅(1-p) + [itex]\bar{X}[/itex]⋅[itex]\bar{X}[/itex]

[itex]\hat{p}[/itex] = (([itex]\bar{X}[/itex])2 + [itex]\bar{X}[/itex] - [itex]\bar{X}[/itex]2) / [itex]\bar{X}[/itex]

Thanks.

I'm not sure what "MME" stands for; In have seen the terms MMSE, MLE, etc., but not MME. Anyway, do you want to take the sample mean [tex]\bar{X} = \frac{\sum_{i=1}^k X_i}{k}?[/tex] If so, do you want [itex]E (\bar{X}) \text{ and } \text{Var}( \bar{X})?[/itex] If that is what you want to get, just use standard formulas for the mean and variance of [itex]\bar{X}[/itex] in terms of the means and variances of the [itex]X_i .[/itex] You will get formulas very different from what you wrote (although I must admit I do not know exactly what you were trying to do).

RGV
 
MME := Method of Moments Estimator
 

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