Finding the n in stokes theorem.

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In the discussion about Stokes' theorem, the user is trying to determine the normal vector (n) for a given vector field F and a circular path in the xy-plane. The curl of F is calculated as -3y²i + 2zj + 2k, and the book identifies n as k, which corresponds to the upward direction along the z-axis. This conclusion is supported by the right-hand rule, where the thumb points in the direction of the normal when fingers curl in the direction of motion around the curve. The user questions the normal direction if the motion were in the negative z direction, but it's clarified that a particle moving in that direction does not imply a clockwise or counterclockwise rotation. Understanding the right-hand rule is essential for correctly applying Stokes' theorem.
Mdhiggenz
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Homework Statement



Hey guys,

I'm having trouble finding the n in stokes theorem.

For example,

F(x,y,z)= z2i+2xj-y3; C is the circle x2 + y2=1 in the xy-plane with counterclockwise orientation looking down the positive z-axis.

∫∫CurlF*n

I know the curl is -3y2i+2zj+2k

The book found that n=k and just multiplied it out. I don't understand where they got that value.

Thanks


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Mdhiggenz said:

Homework Statement



Hey guys,

I'm having trouble finding the n in stokes theorem.

For example,

F(x,y,z)= z2i+2xj-y3; C is the circle x2 + y2=1 in the xy-plane with counterclockwise orientation looking down the positive z-axis.

∫∫CurlF*n

I know the curl is -3y2i+2zj+2k

The book found that n=k and just multiplied it out. I don't understand where they got that value.

Thanks

Imagine grabbing the z axis with your right hand with your thumb pointing up the axis. Are you fingers going counterclockwise when you look down at them. If so, your thumb is pointing the direction of the normal, which in this case is k. It's the "right-hand rule".
 
Thanks for the response, Let's say it was moving in the negative z direction, thus going counterclockwise would it just be -k? Also the book doesn't seem to explain that whole topic very well.
 
Mdhiggenz said:
Thanks for the response, Let's say it was moving in the negative z direction, thus going counterclockwise would it just be -k? Also the book doesn't seem to explain that whole topic very well.

? A particle going in the negative z direction is not going counterclockwise or clockwise. It is going in a straight line.

The right hand rule states that if you have motion around a closed plane curve and you point your right hand fingers along the curve in the direction of motion, your thumb will point in the direction of the corresponding normal to orient the surface for Stokes' theorem.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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