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Homework Help: Finding the new diameter of a metal rod after tensile loading

  1. Sep 12, 2010 #1
    1. The problem statement, all variables and given/known data
    A metal rod with a 0.5 inch diameter is subjected to a 2000 lb tensile load. Calculate the resulting diameter of the rod after loading. Assume that the modulus of elasticity is 10,000,000 psi, Poisson's ratio is 0.33, and the yield strength is 21,000 psi.


    2. Relevant equations

    I'm not really sure how to go about this problem, below is how I started going about it but I'm not sure if I'm on the right track or not.

    3. The attempt at a solution

    σ = P/A = 2000 psi / ( (Pi(0.5^2)/4)) = 1.02 (10^4) psi

    y = (σy - v(σz + σx) ) / E
    = (1.02(10^4) - 0.33 * 0) 10,000,000 psi

    y = 0.00102 in/in

    Now I'm not really sure what next, or even if what I did to this poing is correct.

    Any help will be appreciated!
     
  2. jcsd
  3. Sep 12, 2010 #2

    nvn

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    Homework Helper

    Jim4592: Put a subscript on sigma in your first formula. The subscripts in your second formula are incorrect. Correct those, and try again. Also, always maintain four or five significant digits throughout all your intermediate calculations. Round only the final answer to three (or four) significant digits.
     
  4. Sep 12, 2010 #3
    nvn: thanks for responding, I do use the full value during intermediate calculations but just for the purpose of posting here i shortened it some to save time.

    After reading your response I went back and thought about it some more, here's my new attempt at a solution:

    σx = P/A = 2000 psi / ((Pi * 0.52)/4)) = 1.018591636 (104) psi

    x = ∆L/L = σx/E = 1.01859(104) psi/10,000,000 psi = 0.0010185916

    ∆d = d*v(∆L/L) = 0.5 in * 0.33 * 0.0010185916 = 1.6806762 (10-4) in

    d = do - ∆d = 0.5 in - 1.68067 (10-4) = 0.4998319324 in

    What do you think about my solution now?
     
  5. Sep 12, 2010 #4

    nvn

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    Homework Helper

    Nice work, Jim4592. Regarding significant digits, generally don't list more than four or five (maximum six) significant digits on paper, in your intermediate calculations, even though you use the exact value in your calculator. Then round your final answer to three or four significant digits.

    However, this particular problem might be somewhat of an exception, because of the minute quantities involved. I can see why you might want to round your final answer to up to five or six significant digits here. Nice work.
     
  6. Sep 12, 2010 #5
    alright thanks for all your help!
     
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