Here is the question directly from the book:
f'(x)=x^(-1/3), f(1)=1, f(-1)=-1, find f(x).
The Attempt at a Solution
So there are about ten of these types, and I am very confused. I am confused because if you solve for f(x) with f(a) you get a different value for c than if you solved for f(b).
So finding f(x) I get f(x)=(3/2)x^(2/3) + c
If I make f(x)=1 and x=1, I get the value of c to be -1/2
But if I make f(x)=-1 and x=-1, I get the value of c to be -5/2..
Thank you so much for your help in advance!