Finding the product of multiple normal distributions

Click For Summary

Discussion Overview

The discussion revolves around calculating the probability of a sealed pack of cards containing a foil card based on the mass of the pack. Participants explore the mathematical approach to combine multiple normal distributions representing the masses of foil cards, non-foil cards, and packaging to derive a probability distribution.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • Charij describes a scenario involving a sealed pack of cards with a certain probability of containing a foil card and seeks to calculate this probability based on mass distributions.
  • DrDu suggests a mathematical formulation involving the mass of the foil card, non-foil cards, and packaging, proposing the use of integrals and the Dirac delta function to derive the probability density function (pdf).
  • Charij expresses appreciation for DrDu's guidance and requests additional resources for further understanding.
  • Another participant mentions the characteristic function as a method to calculate the distribution of a sum of variables, linking it to the problem at hand.
  • One participant clarifies that the sum of independent normally distributed random variables results in another normal distribution, suggesting that Charij could look up relevant information on this topic.
  • Charij indicates plans to use convolution of normal distributions and Bayes' Theorem to arrive at the conditional probability of containing a foil card based on weight.

Areas of Agreement / Disagreement

Participants generally agree on the mathematical approach involving the sum of normal distributions and the use of Bayes' Theorem, but there is no explicit consensus on the specific methods or interpretations of the calculations involved.

Contextual Notes

Some assumptions about the independence of the distributions and the applicability of Bayes' Theorem are present but not fully explored. The discussion does not resolve the complexities of integrating the distributions or the implications of the conditional probability.

Charij
Messages
6
Reaction score
0
Hi all,
I've been working on a little side project, but I've hit a road block on the maths for this one. Basically if you imagine a sealed pack of 10 cards, there is a 20% chance that the pack contains one foil (more valuable) card. The mass distribution of the foil cards are (heavier and) different to the non-foil equivelant.

What I would like to do, is calculate the probability of a sealed pack containing a foil card, given the mass of the pack. Essentially I have 3 normal mass distributions for the non-foil cards, foil cards, and packaging. The next step is to combine the 3 normal distributions to give me a bell-curve that shows the probability of a pack containing a foil, given a mass.

I'm guessing I would need to find the product of the packaging, 9 non-foil cards, and 1 foil card distribution; I've struggled to find information on how to do this. Any guidance, or thoughts on this would be most appreciated!

Thanks,
Charij
 
Last edited:
Physics news on Phys.org
So m=m1+m2+m3 where m1 is the mass of the foil card, m2 of the nine non-foil cards and m3 of the packaging.
The pdf for m is then [itex]p(m)=\int dm_1 \int dm_2 \int dm_3 p_1(m_1) p_2(m_2) p_3(m_3) \delta(m-m_1+m_2+m_3)[/itex]
Then use [itex]\delta(x)=1/2\pi \int_{-\infty}^{\infty} dp \exp(ipx)[/itex].
Interchange the order of integration over p and m_1 to m_3.
 
Thanks DrDu,
After reading some wiki, you have put me on the right track! It'll take me a little time to work exactly what you're saying, but it seems to make some sense. Any chance you could link me some material on how to do this?
DrDu said:
Then use δ(x)=1/2π∫∞−∞dpexp(ipx).
Interchange the order of integration over p and m_1 to m_3.

Thanks again,
Charij
 
Charij said:
.

I'm guessing I would need to find the product of the packaging, 9 non-foil cards, and 1 foil card distributionj

You want the distribution of the sum of those things. The sum of independent normally distributed random variables is a normal random variable, so what you can look up on the web is "sum of independent normal (or 'Gaussian' l random variables". Of course, you can also calculate the answer "from first principles" using Dr DuDu's method.

That distribution doesn't give your final answer because you want to calculate the conditional probability that a pack of a given weight contains a foil card. You have to use Bayes rule to do that.
 
Thanks Stephen, that was incredibly useful too! From your information, I plan to use the sum of the normal distributions using convolution. Then use Bayes' Theorem to calculate the probability.

Thanks for your help!
Charij
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 51 ·
2
Replies
51
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K