Finding the Relationship Between Volume and Surface Area of a Sphere

  • Context: Undergrad 
  • Thread starter Thread starter david18
  • Start date Start date
  • Tags Tags
    Confusing Indices
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
david18
Messages
49
Reaction score
0
The Volume and surface area of a sphere is 4/3πr^3 and 4πr^2 respectively. V=4/3πr^3 and S=4πr^2. Write a) S in terms of V and b) V in terms of S

Im stuck on this question... I write out similar base units and stuff but it doesn't seem to work, any help?

-The answer to part a is S=2^2/3 3^2/3 π^1/3 V^2/3
 
Mathematics news on Phys.org
Apparently what you have to is solve each formula for r, and then plug into the the other.

So to solve part a) first, solve your Volume formula for r. then plug that into r in your S formula.

Just do the opposite to solve part b.
 
david18 said:
The Volume and surface area of a sphere is 4/3πr^3 and 4πr^2 respectively. V=4/3πr^3 and S=4πr^2. Write a) S in terms of V and b) V in terms of S

Im stuck on this question... I write out similar base units and stuff but it doesn't seem to work, any help?

-The answer to part a is S=2^2/3 3^2/3 π^1/3 V^2/3

At least use grouping symbols properly if you do not have mathematical typesetting formatting. You intend to say
[tex]\[<br /> V = \left( {\frac{4}{3}} \right)\pi r^3 \quad S = 4\pi r^2 <br /> \][/tex]

You should see through inspection that S is actually contained in the formula for V.
[tex]\[<br /> V = \left( {\frac{1}{3}} \right)(4\pi r^2 )r = \frac{{Sr}}{3}<br /> \][/tex]
Right now, I do not yet see a way to completely eliminate 'r' from the formula. ...Should be possible though.