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Finding the resultant couple moment

  1. Jan 26, 2012 #1
    1. The problem statement, all variables and given/known data
    I attached the question as a picture to this thread


    2. Relevant equations
    M=Fd


    3. The attempt at a solution
    I was taught that the moment produced by two equal but opposite forces is the magnitude of one force multiplied by the distance between the two forces.

    I used Pythagoras to solve for the distances between each of the couples and found sqrt32 and sqrt8 to be these distances.

    Thus
    M1= 150*sqrt32
    M2=200*sqrt8

    and the resultant moment
    =M1-M2
    =283Nm [clockwise]

    This is not the answer, the method the answer key used was breaking up the couples into x and y. I don't understand why my method does not work as well.
     

    Attached Files:

  2. jcsd
  3. Jan 26, 2012 #2

    tiny-tim

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    Science Advisor
    Homework Helper

    hi theBEAST! :smile:
    nooo :redface:

    √32 and √8 are the distances between the points of application of these forces

    the couple uses the distance between the lines of application of the forces :wink:
     
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