Finding the static friction force

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Homework Help Overview

The problem involves a 60-kg person riding down a 20° icy slope while standing on a 3.0-kg bathroom scale, with the goal of determining the static friction force exerted by the scale on the person. The context includes considerations of forces acting on the person and the dynamics of motion down the slope.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the person and question the assumptions made regarding static friction. There is an exploration of Newton's second law in relation to the acceleration of the person down the slope and the implications of maximum static friction.

Discussion Status

The discussion includes attempts to clarify the misunderstanding regarding the static friction force. Some participants suggest that the static friction force may not be at its maximum value and emphasize the need to consider all forces acting on the person. There appears to be a productive direction in understanding the dynamics involved.

Contextual Notes

Participants note that the original poster may have overlooked certain forces contributing to the acceleration of the system, and there is a mention of the equation for maximum static friction being misapplied.

gijungkim
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Homework Statement


A 60-kg person rides down an icy hill of 20° slope while standing on a 3.0-kg flat-bottomed bathroom scale. Assume there is no frictional force between the bottom of the scale and the hill. The static friction force the scale exerts on the person is

Homework Equations

The Attempt at a Solution


I got 211 but the answer is 0 where did I do wrong?
 

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You have left out a force on the person that contributes to the acceleration of the person down the slope.

You have assumed that the force of static friction on the person is ##F_f =\mu N##. But this equation is for the maximum possible static friction force. You cannot assume that the static friction force on the person is at it's maximum possible value. In fact, you will discover that ##F_f =0##.

So, set up Newton's second law for the motion of the person down the slope making sure you include all forces acting on the person.
 
Not sure how you got 211 but if we agree the person-sled system is accelerating gsin20 then every part of the system must also be accelerating the same?
 
TSny said:
You have left out a force on the person that contributes to the acceleration of the person down the slope.

You have assumed that the force of static friction on the person is ##F_f =\mu N##. But this equation is for the maximum possible static friction force. You cannot assume that the static friction force on the person is at it's maximum possible value. In fact, you will discover that ##F_f =0##.

So, set up Newton's second law for the motion of the person down the slope making sure you include all forces acting on the person.
Oh I got it now! Thank you so much!
 

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