Finding the Total Momentum of a Three Particle System

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To find the total momentum of a three-particle system, the momentum of each particle must be calculated by multiplying its mass by its velocity. The correct approach is to sum the individual momenta: p_total = m1*v1 + m2*v2 + m3*v3. Attempts to combine masses and velocities incorrectly led to confusion, as mixing different particles' velocities does not yield meaningful results. Additionally, the velocity of the center of mass can be determined by dividing the total momentum by the total mass of the system. Understanding these principles is crucial for solving the problem accurately.
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Homework Statement



Consider a system consisting of three particles:

m1=5kg, v1=
char68.png
-6,6,7
char69.png
m
char3D.png
s

m2=7kg, v2=
char68.png
8,-6,-7
char69.png
m
char3D.png
s

m3=1kg, v3=
char68.png
6,7,13
char69.png
m
char3D.png
s

What is the total momentum of this system?

What is the velocity of the center of mass of this system?[/B]

Homework Equations



p=m*v

The Attempt at a Solution



I tried (m1+m2)(v1+v2) + (m2+m3)(v2+v3)
and (m1+m2+m3)(v1+v2+v3), neither were correct...
 
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To find the momentum of the system of particles, add the momentums of each of the particles. The momentum of each particle is the mass of each particle multiplied by each particle's respective velocity.
Westin said:
I tried (m1+m2)(v1+v2) + (m2+m3)(v2+v3)
Foiling the first two factors produces m1v1 + m2v2 + m1v2 + m2v1. Why would you multiply the mass of one of the particles by the velocity of another particle? How could this result be meaningful?
 
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