Finding the Value of arctan(1) Without a Calculator

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Homework Help Overview

The discussion revolves around finding the value of arctan(1) without using a calculator, focusing on the properties and definitions of the arctan function within trigonometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the meaning of arctan(1) and its relationship to angles and the tangent function. Some suggest using the unit circle and properties of right triangles to reason through the problem.

Discussion Status

Several participants have provided insights and reasoning related to the problem, with some suggesting methods to derive the value of arctan(1) through definitions and geometric interpretations. There is an ongoing exploration of different approaches without a clear consensus yet.

Contextual Notes

Participants are discussing the problem in the context of a homework assignment, which may impose certain constraints on the methods used to arrive at the solution.

kasse
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All I know about the arctan function is that its domain of def. is the whole real line and that the range of values is (-0,5*pi , 0,5*pi), and also that arctan(0)=0.

But is there a way to know that arctan(1)=(1/4)*pi without recognizing the decimal number the calculator gives?
 
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I think I figured out why after some brainwork:

1=tan (arctan (1))

so because tan(pi/4)=1, arctan(1)=pi/4
 
Last edited:
i don't know if this will help but take the unit circle and reverse it. instead of looking for the angle then finding the value. look for the value then look for the angle that gives you the value. for arcsin(1), you would go along looking a the value of tan(angle) then when you find the value, the x in arcsin(x), you look at the angle that matches up with it.
 
That's easy. Just denote \arctan 1 =x and apply the \tan on both members of the equation. You'll find the eqn \tan x =1 which can easily be solved.

Daniel.
 
The simplest definition of tan(\theta) is "opposite side divided by near side" in a right triangle. If tan(\theta)= 1 then the two legs of the right triangle are the same length- it is an isosceles right triangle. What does that tell you about the angles?
 

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