Finding the values of resistors

  • Thread starter Thread starter ZeeAngel
  • Start date Start date
  • Tags Tags
    Resistors
Click For Summary
SUMMARY

The discussion focuses on solving a resistor value problem using the voltage divider rule and Kirchhoff's Voltage Law (KVL). The user successfully calculates the equivalent resistance (Req) and determines the voltage across it, ultimately finding the value of resistor R2 to be 10 Ohms. The equations utilized include the voltage divider formula and KVL, demonstrating a clear application of circuit analysis principles. The solution highlights the importance of understanding series circuits and the relationships between voltage, current, and resistance.

PREREQUISITES
  • Understanding of voltage divider rule
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of Ohm's Law
  • Concept of equivalent resistance in series circuits
NEXT STEPS
  • Study advanced applications of voltage dividers in complex circuits
  • Explore Kirchhoff's Laws in depth, including practical examples
  • Learn about series and parallel resistor combinations
  • Investigate circuit simulation tools like LTspice for practical circuit analysis
USEFUL FOR

Students studying electrical engineering, hobbyists working on circuit design, and anyone looking to enhance their understanding of resistor networks and circuit analysis techniques.

ZeeAngel
Messages
2
Reaction score
0

Homework Statement


In the problem i have to find the values of resistors using voltage divider, and use KVL to determine the currents.


Homework Equations



Vi= [Ri / (R1+R2+...+Rn)] * Vs

1/Rtotal = 1/R1 + 1/R2 + ... + 1/Rn

Ʃrise + Ʃdrop = 0

The Attempt at a Solution



In order for us to use voltage divider the resistors must be in series.

Req = (40*R2)/(40+R2), but we still don't know the resistance of R2.

However, later I tried to use the KVL equation to find the voltage for Req.

-24+8+Veq = 0 → Veq = 16 V

Then I used the voltage divider equation:

Veq = [Req / (R1 + Req) ]* Vs // but again we have two unknowns here again

And that's the point where I stuck, I know this problem is trivial but my brain cannot come up with anything else to solve this.
 

Attachments

  • Untitled.png
    Untitled.png
    9.2 KB · Views: 558
Physics news on Phys.org
Using KVL, we know that Veq=24V-8V=16V. Using Ohm's Law, we can easily get R2=16V/1.6A=10 Ohms. The rest is obvious! :)
 
Thank you very much :D
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 34 ·
2
Replies
34
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K