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Finding the x and y intercepts

  1. Apr 2, 2013 #1
    f(x)=sin(x)/(1+cos(x))
    So I set it equal to zero to find the y-intercept
    sin(x)=0(1+cos(x))
    x= 0,∏ so the y-int: (0,0) and (0,∏)

    To find the x intercept I would substitute 0 for x so,
    sin(0)/(1+cos(0))=y
    0/1+1=y
    y=0 so the x-int: (0,0)

    would that be right?
     
  2. jcsd
  3. Apr 2, 2013 #2
    Unfortunately, there are a few mistakes. Firstly, you are confusing the x and y axis a bit. To find the y-intercept you would set x=0 (the y axis has equation x=0) and vice versa. Secondly, you listed the points (0,0) and (0,π). You can not have two points on a function with the same x-value. It violates the definition of a function. Surely you meant the points (0,0) and (π,0). Finally, you incorrectly solved the equation [tex] {\frac{\sin x }{1+cos x}}=0 [/tex]

    Not only is it necessary for [itex] sin x [/itex] to be zero, but [itex] 1+ cos x [/itex] must also be nonzero. [itex] x = \pi [/itex] does not fulfill this second requirement.

    Edit: This post should probably be in the Homework & Coursework Questions section.
     
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