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Finding thickness of a cast iron cylinder

  1. Aug 14, 2012 #1
    1. The problem statement, all variables and given/known data

    A cast-iron cylinder of 300mm bore carries a pressure of 30 Newtons per square
    millimetre; what should be its thickness for a unit working stress of 25 newtons per
    square millimetre?


    2. Relevant equations

    ó1 = pd/2t

    t=pd/2tó1


    3. The attempt at a solution

    t=pd/2tó1

    t= 30*300/2*25

    =180mm

    Its got to be wrong as its way too big but im unsure on where im going wrong, any help would be much appreciated.

    'Edit'

    ó1/pd=2t

    25/(30*3000) = 2t

    2t = 0.00277778

    t= 0.0014mm (4dp)

    Maybes this one, im not sure.

    Thanks, Joe
     
    Last edited: Aug 14, 2012
  2. jcsd
  3. Aug 14, 2012 #2

    rock.freak667

    User Avatar
    Homework Helper

    Your first one should be correct. Considering that the pressure is 30 MPa.
     
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