- #1
andrey21
- 476
- 0
If initial vetical velocity is zero, at what time and how fast does a skydiver hit the ground? Assume that g=10m.s^-2
Given that:
y' = -gt + A y' is the vertical velocity
y = -(1/2).g.t^2 +At +B y is the distance above the ground
In order to solve how long takes skydiver to hit ground I did the following:
0 = -(1/2).g.t^2 +(0)t + 4000
4000 = -(1/2).g.t^2
8000 = g.t^2
800 = t^2
t = 28.284 seconds!
Now from here I am unsure how to find the speed at which hits the ground. Help needed sorry for bad formatting!
Given that:
y' = -gt + A y' is the vertical velocity
y = -(1/2).g.t^2 +At +B y is the distance above the ground
In order to solve how long takes skydiver to hit ground I did the following:
0 = -(1/2).g.t^2 +(0)t + 4000
4000 = -(1/2).g.t^2
8000 = g.t^2
800 = t^2
t = 28.284 seconds!
Now from here I am unsure how to find the speed at which hits the ground. Help needed sorry for bad formatting!